Solving $6a + 9 \[U+2265] 8a - 7$ A Step-by-Step Guide

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Introduction

In this article, we will delve into the process of solving the inequality 6a+9\[U+2265]8aβˆ’76a + 9 \[U+2265] 8a - 7. Inequalities, a fundamental concept in mathematics, are mathematical statements that compare two expressions using inequality symbols such as greater than (>>), less than (<<), greater than or equal to (\[U+2265]\[U+2265]), and less than or equal to (\[U+2264]\[U+2264]). Mastering the techniques to solve inequalities is crucial for various mathematical applications and problem-solving scenarios. This guide aims to provide a clear and comprehensive understanding of how to approach and solve this specific inequality, while also highlighting the underlying principles and concepts that apply to solving inequalities in general. We will break down the steps involved, explain the reasoning behind each operation, and provide examples to solidify your understanding. Whether you are a student learning algebra for the first time or someone looking to refresh your skills, this article will serve as a valuable resource. Our focus will be on presenting the solution in a step-by-step manner, ensuring that every step is clearly explained and easy to follow. The goal is not just to provide the answer but to empower you with the knowledge and skills to tackle similar problems with confidence. We will also touch upon the importance of understanding the properties of inequalities and how they differ from equations. Inequalities have unique characteristics, and applying the correct rules is essential for arriving at the correct solution. By the end of this article, you should be able to confidently solve this inequality and have a strong foundation for solving more complex inequalities in the future. Let’s embark on this journey of mathematical exploration and uncover the solution to 6a+9\[U+2265]8aβˆ’76a + 9 \[U+2265] 8a - 7 together.

Step-by-Step Solution

To effectively solve the inequality 6a+9\[U+2265]8aβˆ’76a + 9 \[U+2265] 8a - 7, we will follow a series of algebraic steps, similar to solving equations, but with careful attention to the rules that govern inequalities. The primary goal is to isolate the variable 'a' on one side of the inequality. Here’s a detailed breakdown of each step:

Step 1: Grouping the 'a' Terms

The first step involves grouping the terms containing the variable 'a' on one side of the inequality. To do this, we subtract 6a6a from both sides of the inequality. This operation maintains the balance of the inequality, just like in equations. Subtracting the same value from both sides does not change the solution set. This is a fundamental property of inequalities that allows us to manipulate them while preserving their validity. So, we start with the original inequality:

6a+9\[U+2265]8aβˆ’76a + 9 \[U+2265] 8a - 7

Subtract 6a6a from both sides:

6a+9βˆ’6a\[U+2265]8aβˆ’7βˆ’6a6a + 9 - 6a \[U+2265] 8a - 7 - 6a

This simplifies to:

9\[U+2265]2aβˆ’79 \[U+2265] 2a - 7

By performing this step, we have successfully moved all the 'a' terms to the right side of the inequality, which brings us closer to isolating 'a'. This process is crucial for simplifying the inequality and making it easier to solve. The next steps will focus on further isolating 'a' by dealing with the constant terms.

Step 2: Isolating the Constant Terms

Having grouped the 'a' terms on one side, the next step is to isolate the constant terms on the other side of the inequality. In our current inequality, 9\[U+2265]2aβˆ’79 \[U+2265] 2a - 7, we have a constant term of βˆ’7-7 on the right side. To eliminate this and move it to the left side, we add 77 to both sides of the inequality. Again, this maintains the balance of the inequality and is a valid operation according to the properties of inequalities. Adding the same value to both sides does not alter the solution set.

Starting with:

9\[U+2265]2aβˆ’79 \[U+2265] 2a - 7

Add 77 to both sides:

9+7\[U+2265]2aβˆ’7+79 + 7 \[U+2265] 2a - 7 + 7

This simplifies to:

16\[U+2265]2a16 \[U+2265] 2a

Now, we have successfully isolated the constant terms on the left side, leaving us with an inequality where the 'a' term is the only variable term on the right side. This step is vital because it brings us closer to isolating 'a' completely. The next step will involve dividing both sides by the coefficient of 'a' to finally solve for 'a'.

Step 3: Solving for 'a'

Now that we have 16\[U+2265]2a16 \[U+2265] 2a, the final step to solve for 'a' is to divide both sides of the inequality by the coefficient of 'a', which is 22. Dividing both sides by a positive number maintains the direction of the inequality, a crucial rule to remember when dealing with inequalities. If we were dividing by a negative number, we would need to flip the direction of the inequality sign.

Starting with:

16\[U+2265]2a16 \[U+2265] 2a

Divide both sides by 22:

rac{16}{2} \[U+2265] rac{2a}{2}

This simplifies to:

8\[U+2265]a8 \[U+2265] a

This can also be written as:

a\[U+2264]8a \[U+2264] 8

Therefore, the solution to the inequality 6a+9\[U+2265]8aβˆ’76a + 9 \[U+2265] 8a - 7 is a\[U+2264]8a \[U+2264] 8. This means that any value of 'a' that is less than or equal to 88 will satisfy the original inequality. We have successfully isolated 'a' and found the solution set.

Understanding the Solution

The solution a\[U+2264]8a \[U+2264] 8 to the inequality 6a+9\[U+2265]8aβˆ’76a + 9 \[U+2265] 8a - 7 signifies that the inequality holds true for all values of 'a' that are less than or equal to 8. Understanding the solution is crucial for applying this result in various contexts. This solution set includes 8 itself, as well as all real numbers less than 8. We can visualize this solution on a number line, where the shaded region extends from negative infinity up to and including 8.

Graphical Representation

On a number line, we represent this solution by drawing a closed circle (or bracket) at 8, indicating that 8 is included in the solution, and then shading the line to the left, representing all numbers less than 8. This graphical representation provides a visual understanding of the solution set. It clearly shows the range of values for 'a' that satisfy the inequality.

Verification

To verify the solution, we can test values within and outside the solution set in the original inequality. For example:

  • Let's test a=8a = 8:

    6(8)+9\[U+2265]8(8)βˆ’76(8) + 9 \[U+2265] 8(8) - 7

    48+9\[U+2265]64βˆ’748 + 9 \[U+2265] 64 - 7

    57\[U+2265]5757 \[U+2265] 57 (True)

  • Now, let's test a value less than 8, say a=0a = 0:

    6(0)+9\[U+2265]8(0)βˆ’76(0) + 9 \[U+2265] 8(0) - 7

    9\[U+2265]βˆ’79 \[U+2265] -7 (True)

  • Finally, let's test a value greater than 8, say a=9a = 9:

    6(9)+9\[U+2265]8(9)βˆ’76(9) + 9 \[U+2265] 8(9) - 7

    54+9\[U+2265]72βˆ’754 + 9 \[U+2265] 72 - 7

    636563 65 (False)

These tests confirm that our solution a\[U+2264]8a \[U+2264] 8 is correct. Values within the solution set make the inequality true, while values outside the solution set make it false. This process of verification is essential to ensure the accuracy of our solution.

Implications

The solution to an inequality has practical implications in various real-world scenarios. For instance, it can be used to determine the range of values that satisfy certain conditions in optimization problems, resource allocation, and decision-making processes. Implications of understanding the solution help in applying these concepts effectively.

Common Mistakes and How to Avoid Them

When solving inequalities, it's easy to make mistakes if you're not careful. However, being aware of common mistakes can help you avoid them and ensure you arrive at the correct solution. Here are some common pitfalls and tips on how to steer clear of them:

Mistake 1: Forgetting to Flip the Inequality Sign

The most common mistake is forgetting to flip the inequality sign when multiplying or dividing both sides by a negative number. This is a critical rule in inequality manipulation. When you multiply or divide by a negative value, you are essentially reversing the order of the number line. To maintain the correct relationship between the expressions, you must flip the inequality sign.

How to Avoid: Always remember to flip the inequality sign when multiplying or dividing by a negative number. Double-check your steps if you perform such an operation. A helpful mnemonic is to associate "negative" with "flip."

Mistake 2: Incorrectly Combining Like Terms

Another common mistake is incorrectly combining like terms. This can happen when terms are not properly identified or when arithmetic errors are made. It's crucial to ensure that you are only combining terms that have the same variable and exponent or are constant terms.

How to Avoid: Take your time and carefully identify like terms before combining them. Use a highlighter or different colors to mark like terms. Double-check your arithmetic to avoid errors in addition or subtraction.

Mistake 3: Distributing Negatives Incorrectly

When dealing with expressions that involve distributing a negative sign, it's easy to make mistakes. The negative sign must be distributed to every term inside the parentheses, and forgetting to do so can lead to an incorrect solution.

How to Avoid: Write out the distribution explicitly to ensure you don't miss any terms. For example, instead of directly simplifying βˆ’(x+3)-(x + 3), write it as βˆ’1βˆ—(x+3)-1 * (x + 3) and then distribute. This visual reminder can help prevent errors.

Mistake 4: Misunderstanding the Solution Set

A common mistake is misunderstanding what the solution set represents. For example, if the solution is x>3x > 3, it means that all values greater than 3 satisfy the inequality, but 3 itself does not. It's important to interpret the inequality sign correctly.

How to Avoid: Visualize the solution set on a number line. This can help you understand the range of values that satisfy the inequality. Pay close attention to whether the inequality includes the endpoint (using \[U+2265]\[U+2265] or \[U+2264]\[U+2264]) or excludes it (using >> or 55, a=0a = 0, and a=7a = 7, while incorrectly concluding that 8 is the only solution.

How to Avoid: Write out the steps clearly and show all your work. This makes it easier to review your solution and identify any errors. Verification by substituting values into the original inequality is an essential step in the solution process.

Conclusion

In conclusion, we have successfully solved the inequality 6a+9\[U+2265]8aβˆ’76a + 9 \[U+2265] 8a - 7, arriving at the solution a\[U+2264]8a \[U+2264] 8. This journey has not only provided us with the solution but has also reinforced the fundamental principles of solving inequalities. We have walked through the step-by-step process, from grouping like terms to isolating the variable, emphasizing the importance of each operation and the rules that govern inequalities. Understanding these rules and applying them correctly is paramount to solving inequalities accurately. Furthermore, we delved into the significance of the solution set, understanding that a\[U+2264]8a \[U+2264] 8 represents all real numbers less than or equal to 8, and explored how to verify the solution through testing values within and outside the solution set. This verification process is a crucial step in ensuring the accuracy of our work.

Moreover, we addressed common mistakes that students often make when solving inequalities, such as forgetting to flip the inequality sign when multiplying or dividing by a negative number, incorrectly combining like terms, misapplying the distributive property, misunderstanding the solution set, and stopping at an intermediate step. By being aware of these potential pitfalls and adopting strategies to avoid them, you can significantly improve your problem-solving accuracy.

Solving inequalities is not just a mathematical exercise; it is a skill with practical applications in various fields, including science, engineering, economics, and computer science. The ability to solve inequalities allows us to model and analyze real-world situations, make informed decisions, and optimize processes. The principles and techniques discussed in this article serve as a foundation for tackling more complex mathematical problems and real-world challenges.

As you continue your mathematical journey, remember that practice is key to mastery. The more you practice solving inequalities, the more confident and proficient you will become. Embrace the challenges, learn from your mistakes, and never stop exploring the fascinating world of mathematics. The skills you acquire in solving inequalities will undoubtedly serve you well in your academic pursuits and beyond. We encourage you to apply these techniques to a variety of problems, thereby solidifying your understanding and enhancing your problem-solving capabilities.