Polynomial Division Explained Step-by-Step

by ADMIN 43 views
Iklan Headers

Polynomial division can seem daunting, but with a methodical approach, it becomes a manageable task. This comprehensive guide will walk you through the process of dividing the polynomial (3x5βˆ’14x3+10x2+11x+10)(3x^5 - 14x^3 + 10x^2 + 11x + 10) by the binomial (x2+1)(x^2 + 1). We'll break down each step, ensuring clarity and understanding. Whether you're a student tackling algebra or simply refreshing your math skills, this article will equip you with the knowledge to confidently divide polynomials.

Understanding Polynomial Division

Before we dive into the specifics of our example, let's establish a foundational understanding of polynomial division. Polynomial division is essentially the reverse process of polynomial multiplication. Just as long division helps us divide numbers, polynomial division allows us to divide algebraic expressions. The goal is to find a quotient and a remainder when one polynomial is divided by another. The key components are the dividend (the polynomial being divided), the divisor (the polynomial we are dividing by), the quotient (the result of the division), and the remainder (the portion left over, if any).

The process mirrors long division with numbers, but instead of dealing with digits, we manipulate terms with variables and exponents. Mastering polynomial division is crucial for simplifying expressions, solving equations, and understanding more advanced algebraic concepts. The divisor (x2+1)(x^2 + 1) plays a vital role in determining how we approach the division process. We look for terms in the dividend that, when divided by x2x^2, will give us a term to start our quotient. Remember, the aim is to systematically eliminate terms in the dividend until we arrive at a remainder that has a lower degree than the divisor. Polynomial division isn't just a mechanical process; it's a way of dissecting polynomials and understanding their structure. The quotient and remainder we obtain provide valuable insights into the relationship between the dividend and the divisor. In our specific example, understanding the interplay between the terms will help us simplify the expression and arrive at the correct solution. By the end of this guide, you'll not only be able to perform the division but also appreciate the underlying mathematical principles at play.

Setting Up the Problem

To begin, let's set up the long division problem. Write the dividend (3x5βˆ’14x3+10x2+11x+10)(3x^5 - 14x^3 + 10x^2 + 11x + 10) inside the long division symbol and the divisor (x2+1)(x^2 + 1) outside. It's crucial to ensure that all powers of xx are represented in the dividend, even if their coefficients are zero. In this case, we're missing an x4x^4 term, so we'll insert a 0x40x^4 term as a placeholder. This ensures proper alignment and prevents errors during the division process.

The setup now looks like this:

 x^2 + 1 | 3x^5 + 0x^4 - 14x^3 + 10x^2 + 11x + 10

This meticulous setup is a critical first step. It's analogous to ensuring that the digits are correctly aligned in numerical long division. The placeholder term, 0x40x^4, is particularly important. Without it, we might misalign terms during the subtraction steps, leading to an incorrect result. Think of it as a zero in a number; it holds a place and maintains the value of the other digits. Similarly, 0x40x^4 holds the place for the x4x^4 term and ensures that the subsequent terms are correctly aligned based on their powers of xx. This attention to detail is a hallmark of accurate polynomial division. Taking the time to set up the problem correctly will save you from potential mistakes and make the entire process smoother. So, remember, always check for missing terms and use zero coefficients as placeholders to maintain the integrity of the polynomial structure throughout the division.

Step-by-Step Polynomial Division

Now, let's proceed with the division. Our first goal is to find a term that, when multiplied by the divisor (x2+1)(x^2 + 1), will eliminate the leading term of the dividend, which is 3x53x^5. To do this, we divide the leading term of the dividend (3x53x^5) by the leading term of the divisor (x2x^2). This gives us 3x33x^3. Write 3x33x^3 above the division symbol, aligned with the x3x^3 term in the dividend. Next, multiply the entire divisor (x2+1)(x^2 + 1) by 3x33x^3, which gives us 3x5+3x33x^5 + 3x^3. Write this result below the corresponding terms in the dividend.

 3x^3
 x^2 + 1 | 3x^5 + 0x^4 - 14x^3 + 10x^2 + 11x + 10
 3x^5 + 3x^3

Now, subtract the result (3x5+3x3)(3x^5 + 3x^3) from the corresponding terms in the dividend. This gives us (3x5βˆ’3x5)+(0x4βˆ’0x4)+(βˆ’14x3βˆ’3x3)+10x2+11x+10(3x^5 - 3x^5) + (0x^4 - 0x^4) + (-14x^3 - 3x^3) + 10x^2 + 11x + 10, which simplifies to βˆ’17x3+10x2+11x+10-17x^3 + 10x^2 + 11x + 10. Bring down the next term from the dividend, which is +10+10.

 3x^3
 x^2 + 1 | 3x^5 + 0x^4 - 14x^3 + 10x^2 + 11x + 10
 - (3x^5 + 3x^3)
 -----------------------------
 -17x^3 + 10x^2 + 11x + 10

Repeat the process. Divide the new leading term (βˆ’17x3)(-17x^3) by the leading term of the divisor (x2)(x^2), which gives us βˆ’17x-17x. Write βˆ’17x-17x above the division symbol, aligned with the xx term in the dividend. Multiply the divisor (x2+1)(x^2 + 1) by βˆ’17x-17x, which gives us βˆ’17x3βˆ’17x-17x^3 - 17x. Write this result below the corresponding terms.

 3x^3 - 17x
 x^2 + 1 | 3x^5 + 0x^4 - 14x^3 + 10x^2 + 11x + 10
 - (3x^5 + 3x^3)
 -----------------------------
 -17x^3 + 10x^2 + 11x + 10
 -17x^3 - 17x

Subtract the result (βˆ’17x3βˆ’17x)(-17x^3 - 17x) from the corresponding terms. This gives us (βˆ’17x3βˆ’(βˆ’17x3))+10x2+(11xβˆ’(βˆ’17x))+10(-17x^3 - (-17x^3)) + 10x^2 + (11x - (-17x)) + 10, which simplifies to 10x2+28x+1010x^2 + 28x + 10.

 3x^3 - 17x
 x^2 + 1 | 3x^5 + 0x^4 - 14x^3 + 10x^2 + 11x + 10
 - (3x^5 + 3x^3)
 -----------------------------
 -17x^3 + 10x^2 + 11x + 10
 - (-17x^3 - 17x)
 -----------------------------
 10x^2 + 28x + 10

Again, repeat the process. Divide the new leading term (10x2)(10x^2) by the leading term of the divisor (x2)(x^2), which gives us 1010. Write +10+10 above the division symbol, aligned with the constant term in the dividend. Multiply the divisor (x2+1)(x^2 + 1) by 1010, which gives us 10x2+1010x^2 + 10. Write this result below the corresponding terms.

 3x^3 - 17x + 10
 x^2 + 1 | 3x^5 + 0x^4 - 14x^3 + 10x^2 + 11x + 10
 - (3x^5 + 3x^3)
 -----------------------------
 -17x^3 + 10x^2 + 11x + 10
 - (-17x^3 - 17x)
 -----------------------------
 10x^2 + 28x + 10
 10x^2 + 10

Subtract the result (10x2+10)(10x^2 + 10) from the corresponding terms. This gives us (10x2βˆ’10x2)+28x+(10βˆ’10)(10x^2 - 10x^2) + 28x + (10 - 10), which simplifies to 28x28x. Since the degree of 28x28x (which is 1) is less than the degree of the divisor x2+1x^2 + 1 (which is 2), we have reached the remainder.

 3x^3 - 17x + 10
 x^2 + 1 | 3x^5 + 0x^4 - 14x^3 + 10x^2 + 11x + 10
 - (3x^5 + 3x^3)
 -----------------------------
 -17x^3 + 10x^2 + 11x + 10
 - (-17x^3 - 17x)
 -----------------------------
 10x^2 + 28x + 10
 - (10x^2 + 10)
 -----------------------------
 28x

Expressing the Result

The quotient is 3x3βˆ’17x+103x^3 - 17x + 10, and the remainder is 28x28x. Therefore, we can express the result of the division as:

(3x^5 - 14x^3 + 10x^2 + 11x + 10) ext{ Γ· } (x^2 + 1) = 3x^3 - 17x + 10 + rac{28x}{x^2 + 1}

This is the simplified form of the division, expressing the original polynomial division problem in terms of its quotient and remainder. The fraction 28xx2+1\frac{28x}{x^2 + 1} represents the remainder divided by the divisor, which is a crucial part of the complete answer. The quotient, 3x3βˆ’17x+103x^3 - 17x + 10, represents the whole polynomial result of the division, while the remainder term accounts for the portion that couldn't be evenly divided. This comprehensive representation is essential for various mathematical applications, such as solving equations or further simplifying expressions. Always remember to include the remainder term when expressing the final result of a polynomial division. It completes the picture and provides a precise representation of the relationship between the dividend, divisor, quotient, and remainder.

Conclusion

In this guide, we have meticulously walked through the process of dividing the polynomial (3x5βˆ’14x3+10x2+11x+10)(3x^5 - 14x^3 + 10x^2 + 11x + 10) by the binomial (x2+1)(x^2 + 1). We emphasized the importance of setting up the problem correctly, including the use of placeholder terms, and then systematically performed the long division. The key steps involved dividing leading terms, multiplying the quotient term by the divisor, subtracting, and bringing down the next term. This iterative process continued until the degree of the remainder was less than the degree of the divisor. The final result, expressed as 3x3βˆ’17x+10+28xx2+13x^3 - 17x + 10 + \frac{28x}{x^2 + 1}, accurately represents the quotient and remainder of the division.

Polynomial division, while seemingly complex at first, becomes more manageable with practice and a clear understanding of the underlying principles. The techniques discussed here are applicable to a wide range of polynomial division problems. Remember to always double-check your work, especially the subtraction steps, to avoid common errors. By mastering polynomial division, you gain a valuable tool for simplifying expressions, solving equations, and tackling more advanced algebraic concepts. The application of polynomial division extends beyond basic algebra, playing a crucial role in calculus, abstract algebra, and various engineering disciplines. So, continue practicing, and you'll find that dividing polynomials becomes a skill you can confidently apply in your mathematical journey. Remember, the systematic approach and attention to detail are the keys to success in polynomial division.