Matching Equations Parallel And Perpendicular To A Line

by ADMIN 56 views
Iklan Headers

This guide will help you understand how to match linear equations with their corresponding geometric properties, specifically perpendicularity and parallelism. We'll explore how to determine the equations of lines that meet these conditions, given a point and the equation of another line. This is a crucial concept in coordinate geometry, with applications in various fields, including engineering, physics, and computer graphics. Let's dive in!

Understanding Slopes of Parallel and Perpendicular Lines

The core concept for solving this type of problem lies in understanding the relationship between the slopes of parallel and perpendicular lines.

  • Parallel Lines: Parallel lines have the same slope. If two lines are parallel, their slopes are equal. Mathematically, if line 1 has slope m1 and line 2 has slope m2, then for parallel lines, m1 = m2. This means they have the same steepness and direction, and will never intersect.

  • Perpendicular Lines: Perpendicular lines intersect at a right angle (90 degrees). The slopes of perpendicular lines are negative reciprocals of each other. If line 1 has slope m1 and line 2 has slope m2, then for perpendicular lines, m1 * m2* = -1, or m2 = -1/m1. This indicates an inverse relationship where one slope is the negative reciprocal of the other.

Understanding these relationships is fundamental to finding equations that satisfy the given conditions. Let's delve into the specifics of solving the problems presented.

Finding the Equation of a Line Perpendicular to a Given Line

The Equation Perpendicular to y = -1/3 x + 4 Through (-4, 2)

The problem asks us to find the equation of a line that is perpendicular to the line y = -1/3 x + 4 and passes through the point (-4, 2). This involves several steps, each building upon the previous one to arrive at the final equation.

First, we need to identify the slope of the given line. The equation y = -1/3 x + 4 is in slope-intercept form (y = mx + b), where m represents the slope and b represents the y-intercept. In this case, the slope (m1) of the given line is -1/3. Understanding the slope-intercept form is key to quickly extracting the slope of any linear equation.

Next, we need to determine the slope of the perpendicular line. As we discussed earlier, the slopes of perpendicular lines are negative reciprocals of each other. So, if the slope of the given line is -1/3, the slope (m2) of the perpendicular line is the negative reciprocal of -1/3, which is 3. This step is crucial because it sets the direction for our new line.

Now that we have the slope of the perpendicular line (m2 = 3) and a point it passes through (-4, 2), we can use the point-slope form of a linear equation to find the equation of the line. The point-slope form is given by y - y1 = m( x - x1), where (x1, y1) is the given point and m is the slope. Substituting the values, we get y - 2 = 3( x - (-4)), which simplifies to y - 2 = 3( x + 4).

Finally, we need to convert the equation from point-slope form to slope-intercept form (y = mx + b) or standard form (Ax + By = C) to match the answer choices. Let's convert it to slope-intercept form first. Expanding the equation, we get y - 2 = 3x + 12. Adding 2 to both sides, we get y = 3x + 14. Now, let's convert it to standard form. Subtracting 3x from both sides, we have -3x + y = 14. Multiplying by -1 to make the coefficient of x positive, we get 3x - y = -14. Now we have the equation in both slope-intercept and standard forms, allowing us to match it with the appropriate form in the provided options.

Finding the Equation of a Line Parallel to a Given Line

The Equation Parallel to y = -3 x + 2 Through (2, 3)

This problem requires finding the equation of a line that is parallel to the line y = -3x + 2 and passes through the point (2, 3). The process is similar to the perpendicular case, but with a crucial difference in how we determine the slope.

First, we need to identify the slope of the given line. Again, the equation y = -3x + 2 is in slope-intercept form. The slope (m1) of the given line is -3. Recognizing the slope-intercept form immediately gives us the slope, saving time and reducing the chance of errors.

Since the lines are parallel, they have the same slope. Therefore, the slope (m2) of the line we are trying to find is also -3. This is the key difference from the perpendicular case, where we needed to calculate the negative reciprocal. Parallel lines maintain the same steepness and direction, so their slopes are identical.

Now, we have the slope (m2 = -3) and a point (2, 3) that the line passes through. We can use the point-slope form of a linear equation: y - y1 = m( x - x1). Substituting the values, we get y - 3 = -3( x - 2).

Finally, we convert the equation to slope-intercept form or standard form. Expanding the equation, we get y - 3 = -3x + 6. Adding 3 to both sides, we get y = -3x + 9. Now, let's convert it to standard form. Adding 3x to both sides gives 3x + y = 9. Having both forms of the equation allows us to easily match it to the given options.

Matching the Equations

Now that we've derived the equations, let's match them to the options provided. The goal is to connect the calculated equations with their corresponding descriptions, reinforcing the understanding of parallel and perpendicular relationships.

  1. An equation perpendicular to y = -1/3 x + 4 through (-4, 2): We found the equation to be y = 3x + 14 (slope-intercept form) or 3x - y = -14 (standard form). We need to look for an equation in the provided options that matches either of these forms.

  2. An equation parallel to y = -3 x + 2 through (2, 3): We found the equation to be y = -3x + 9 (slope-intercept form) or 3x + y = 9 (standard form). We'll search for a matching equation in the options.

By comparing the derived equations with the options, we can definitively match the geometric descriptions with their corresponding algebraic representations. This step solidifies the link between the visual concept of lines and their mathematical expressions.

In the given problem, the options include the equation -x + 3y = 7. Let's analyze this equation to see if it matches either of our derived equations.

To do this, we can rearrange the given equation into slope-intercept form (y = mx + b). Starting with -x + 3y = 7, we add x to both sides to get 3y = x + 7. Then, dividing both sides by 3, we get y = (1/3)x + 7/3.

Now we can see that the slope of this line is 1/3. This is neither the slope of the line perpendicular to y = -1/3 x + 4 (which was 3) nor the slope of the line parallel to y = -3x + 2 (which was -3). Therefore, -x + 3y = 7 does not match either of the conditions we calculated. This highlights the importance of accurately determining slopes and using the correct forms of equations.

Let's analyze if -x + 3y = 7 is the line perpendicular to y = -1/3 x + 4. If -x + 3y = 7, then the slope of the line is 1/3. However, we are looking for the equation of a line with slope 3 that passes through the point (-4, 2). Therefore, it is not the correct answer.

To summarize, when matching equations, always convert them to a standard form (like slope-intercept or standard form) to easily compare slopes and intercepts. And remember, parallel lines have the same slope, while perpendicular lines have negative reciprocal slopes.

Strategies for Solving Matching Problems

Matching problems, like the one presented, are common in mathematics and require a systematic approach. Here's a breakdown of effective strategies to tackle such problems, especially in the context of linear equations and geometric properties:

  • Identify Key Information: Start by carefully reading and understanding the problem statement. Identify the given information, such as the equations of lines, points, and the required geometric relationships (parallel or perpendicular). Extracting this information clearly is the first step to a successful solution.

  • Understand Geometric Relationships: Recall the fundamental relationships between slopes of parallel and perpendicular lines. Parallel lines have the same slope, while perpendicular lines have slopes that are negative reciprocals of each other. This knowledge is the cornerstone of solving these types of problems.

  • Calculate Slopes: Determine the slopes of the given lines. If the equation is in slope-intercept form (y = mx + b), the slope m is readily available. If the equation is in standard form (Ax + By = C), rearrange it to slope-intercept form to find the slope, or use the formula m = -A/B. Accurate slope calculation is crucial for determining parallel and perpendicular relationships.

  • Determine the Required Slope: Based on the geometric relationship, determine the slope of the line you need to find. If it's parallel, use the same slope as the given line. If it's perpendicular, calculate the negative reciprocal of the given line's slope. This step bridges the gap between the given information and the desired equation.

  • Use Point-Slope Form: If you have a point and a slope, the point-slope form of a linear equation (y - y1 = m( x - x1)) is a powerful tool. Substitute the given point (x1, y1) and the calculated slope m into the equation. This form directly incorporates the essential information and provides a stepping stone to the final equation.

  • Convert to Standard or Slope-Intercept Form: Convert the equation from point-slope form to the form that matches the answer choices or the requirements of the problem (usually slope-intercept form y = mx + b or standard form Ax + By = C). Expanding and rearranging the equation allows you to compare it with the given options and identify the correct match.

  • Eliminate Incorrect Options: If you can quickly identify characteristics that don't match (e.g., incorrect slope, wrong y-intercept, or not passing through the given point), eliminate those options. This strategy narrows down the possibilities and increases your chances of selecting the correct answer.

  • Verify Your Answer: After finding a potential match, verify that it satisfies all the conditions of the problem. Does the line have the correct slope? Does it pass through the given point? Does it satisfy the perpendicular or parallel relationship? This final check ensures accuracy and confidence in your solution.

By employing these strategies, you can confidently approach matching problems involving linear equations and geometric properties. The key is to break down the problem into manageable steps, apply the relevant concepts, and carefully verify your results.

Common Mistakes to Avoid

When working with linear equations and their geometric properties, certain mistakes are common. Being aware of these pitfalls can help you avoid them and improve your accuracy in solving problems.

  • Incorrectly Calculating Negative Reciprocals: A frequent mistake is incorrectly calculating the negative reciprocal of a slope. Remember that to find the negative reciprocal, you need to flip the fraction and change its sign. For example, the negative reciprocal of -2/3 is 3/2, not -3/2 or -2/3. Double-checking this calculation is crucial for perpendicularity problems.

  • Confusing Parallel and Perpendicular Slopes: It's easy to mix up the rules for parallel and perpendicular slopes. Parallel lines have the same slope, while perpendicular lines have negative reciprocal slopes. A quick mental check –